Seg AM is the median of Triangle ABC. If BC=16cm, AB2+AC2 = 200 cm² then AM= ?
6cm
12cm
18cm
20cm
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Answer:
Given,
AB2+AC2=290,AM=8
AB2+AC2=2(AM2+BM2)
290=2(82+BM2)
145=64+BM2
⇒BM=9cm
BC=BM+MC
=2BM
=2×9
=18cm
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