Question

Seg CD is the median of ️ ABC. Point D is the midpoint of seg AB.A (️ADC)/A(️BDC)=​

Answer 1

Answer:

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Direct Solution :

Median Divided triangle in 2 Equal area triangle

=> A(∆ADC) = A(∆BDC)

=> A(∆ADC)/A(∆BDC) = 1

Detailed :

Draw CM ⊥ AB , AD , BD as D is point of AB

Area of Triangle = (1/2) * base * Height

=> A(∆ADC) = (1/2) * AD * CM

A(∆BDC) = (1/2) * BD * CM

AD = BD as D is the midpoint of seg. AB

=> A(∆BDC) = (1/2) * AD * CM

A(∆ADC) = A(∆BDC) = (1/2) * AD * CM

Hence A(∆ADC)/A(∆BDC) = 1