Seg PM and seg PN are congruent chords of a circle with centre C. Show that the ray PC is the bisector of angle NPM.
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Answer:In ΔCPM and ΔCPN,
CP=CP
CM=CN(radius)
MP=NP(congruent chords)
In ΔCPM and ΔCPN,
CP=CP
CM=CN(radius)
MP=NP(congruent chords)
⇒ By S.S.S congruency,
ΔCPM≅ΔCPN
⇒∠MPC=∠NPC
⇒∠x=∠y.
⇒ By S.S.S congruency,
ΔCPM≅ΔCPN
⇒∠MPC=∠NPC
⇒∠x=∠y.
Step-by-step explanation:
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