Question

*Seg PM is a median of △PQR. If PQ = 40, PR = 42 and QR = 58 then find length of PM.*

1️⃣ 25
2️⃣ 20
3️⃣ 21
4️⃣ 29​

Answer 1

In PQR, point m is the midpoints of side QR.

QM=MR= ½QR

PQ² + PR² = 2PM² + 2 QM² {by A]

( 40 )² + ( 42 )² = 2( 29 )² + 2QM²

1600 + 1764 = 1682 + 2QM²

3364 - 1682 = 2QM²

QM² = 841

QM = 29

QR = 2×29

QR = 58

HENCE, QR = 58

In △PQR;

PQ=8,QR=5,PR=3 

(8)2=8, (5)2=5, (3)2=3 and 3+5=8 

Thus, the longest length of the sides of the triangle is PQ=8, opposite to ∠R

The square of the largest numbers is equal to the sum of the square of the other two numbers.

∴△PQR form a right-angled triangle, where angle R is of 90∘

Answer 2

Answer:

Step-by-step explanation:

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