Seg PQ is parallel to y -axis and co-ordinates of point P are(1,3) , then co-ordinates of point Q can be
Answers
Given info : segment PQ is parallel to y - axis and coordinates of point P are (1, 3).
To find : the coordinates of point Q can be..
solution : a/c to question,
PQ is parallel to y - axis.
so, slope of PQ = slope of y axis
slope of PQ = 1/0
let point Q is (x , y)
then, slope of PQ = (y - 3)/(x - 1) = 1/0
⇒x - 1 = 0
⇒x = 1 and y ∈ R means, y can be any real number
i.e., y = 0, 1, -1, 2, √3 , -3 ...
Therefore coordinates of point P can be (1 , y) where y belongs to all real numbers.
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