Question

seg RM and seg RN are tangent segments of a circle with centre O. prove that OR bisects angle MRN and angle MON

Answer 1

Answer:

In ∆ MRN and ∆ MON, we have

OM = ON …… [radius of the circle]

OR = OR ……. [common side for both the triangle]

Seg RM =  seg RN ……. [Tangents segments from an external point to the circle are congruent to each other]

∴ By SSS congruence criterion, we get

∆ MRN ≅ ∆ MON

Thus, by using the property of Corresponding Parts of Congruent Triangles i.e., CPCT, we get

∠RON = ∠ROM ….. (i)

And,

∠MRO = ∠NRO ….. (ii)

Now, from (i) & (ii), we can say

OR bisects ∠MRN and ∠MON

Hence proved

Answer 2

Answer:

OR bisect MRN and MON

Step-by-step explanation:

because OR is Middle from both side hence

proved