segment AB is a diameter of a circle. C is a point on the circumference such that in triangle ABC, angle B is less by 10° then angle A find the measure of all angles of triangle ABC.
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Answer:
90°, 50° and 40°.
Step-by-step explanation:
Given,
AB is the diameter of the circle,
And, C is the point on the circumference of the circle,
⇒ ∠ACB is an angle inscribed in semicircle.
Since, an angle inscribed in semicircle is complementary,
⇒ m∠ACB = 90°
Let in triangle ABC,
m∠ BAC = x,
According to the question,
m∠ ABC = x - 10°
We know that,
m∠ACB + m∠ BAC + m∠ ABC = 180°
90° + x + x - 10° = 180°
2x + 80° = 180°
2x = 100° ⇒ x = 50°,
Hence, the measurement of all angles of triangle ABC,
m∠ACB = 90°, m∠ BAC = 50° and m∠ ABC = 40°
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