Question

Segment AB is a diameter of a circle. C is a point on the circumference such that in ∆ABC angleB is less by 10° than angle A. Find the measure of all angle of ∆ABC

Answer 1

Answer:Angle A = 50

Angle B = 40

Angle C = 90

Step-by-step explanation:

In Triangle ABC, Angle ACB = 90       ANGLE IN A SEMICIRCLE

Let Angle A be x.

hence Angle B = x-10                           GIVEN

Angle (A + B + C) = 180                        SUM  OF ANGLES OF A TRIANGLE

-> x + (x-10) + 90 = 180

-> 2x + 80 = 180

-> 2x = 100

-> x = 50

Hence, Angle A = x = 50 & Angle B = x-10 = 40