Question

Sehgal started to move in the direction of
East and moved 6 m. Then he turned to his
right and moved 6 m. After this he walked 20
m in the direction of North-west. Now how far
is he from his starting point?​

Answer 1

6m towards East (means at right direction)
Then 6m right means towards south

Then 20m towards northwest

Hence by Pythagotus theorem [ root(6^2+6^2)]=length of the slope
So, (root36+root36) =length of slope

That is 12
Hence:- 12- 20(as he walked towards northwest)
Is 6m from the starting point

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Answer 2

Answer:

Sehgal is 11.5m away from his starting point.

Step-by-step explanation:

Consider that 'O' is the staring point.

Sehgal started to walk in the east direction and covered distance, OA = 6m

Then turn right covered distance, AB = 6m

Then he walked in north west direction and covered distance, AC = 20m

From the attached figure below,

The right angle triangle OAB, we can find OB by using Pythagoras theorem;

$OB^{2}= OA^2+AB^2$

$OB=\sqrt{ OA^2+AB^2}$

$OB=\sqrt{6^2+6^2}$

$OB=\sqrt{36+36}$

$OB=\sqrt{72}$

OB = 8.495m ≈ OB = 8.50m

Now OC is distance between starting point and end point.

Now the distance, OC = BC - OB

OC = 20m - 8.50m

OC = 11.5m

Therefore, he is 11.5m away from the starting point.