Select correct option from the given options.
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integral of dx/1+x^2 is arctan x
therefore evaluating the integral with lower limit 1 and upper limit √3:
=arctan 1-arctan√3
=π/3-π/4
=π/12
option (b) is correct
Regards!
therefore evaluating the integral with lower limit 1 and upper limit √3:
=arctan 1-arctan√3
=π/3-π/4
=π/12
option (b) is correct
Regards!
saloni2019sharma:
error
wo arctan3^1/2-arctan1 hoga
but niche tumne sahi likh diya
arctan √3 π/3 hota hai and arctan 1 π/4 hai so π/3-π/4 will give you π/12, whereas -π/12 in the other way around
oh sorry
ha silly mistake Kia Meine
photo khiske bhejna chahiye tha, my bad!
fine
not to worry
it happens
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so you have B as answer...
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