Question

Select designation, sum(salary) from desig groupby designation having count(*)>=2; Please explain the purpose of count(*)>=2 here.

Answer 1

Answers:(vi) SELECT COUNT (DISTINT DESIGNATION ) FROM EMPSALARY

Ans: 4

(vii) SELECT DESIGNATION , SUM(SALARY) FROM EMPSALARY GROUP BY DESIGNATION HAVING COUNT(*)>2;

Ans: Designation Sum(Salary)

Manager 215000

Clerk 135000

(viii) SELECT SUM (BENEFITS) FROM EMPSALARY WHERE DESIGNATION=’Clerk’;

Ans: 32000

OUTSIDE DELHI 2005:

5) Consider the following tables WORKERS and DESIG. Write SQL commands for the statements (i) to (iv) and give outputs for SQL queries (v) to (viii). WORKERS

W_ID

FIRSTNAME LASTNAME ADDRESS CITY

102

Sam Tones 33 Elm St. Paris

105

Sarah Ackerman 44 U.S.110 NewYork

144

Manila Sengup ta 24 Friends Street New Delhi

210

George Smith 83 First Street Howard

255

Mary Jones 842 Vine Ave. Losantiville

300

Robert Samuel 9 Fifth Cross Washington

335

Henry Williams 12Moore Street Boston

403

Ronny Lee 121 Harrison St. New York

451

Pat Thomps on 11 Red Road Paris

DESIG

W_ID

SALARY BENEFITS DESIGINA TION

102 75000 15000 Manager

105 85000 25000 Director

144 70000 15000 Manager

210 75000 12500 Manager

255 50000 12000 Clerk

300 45000 10000 Clerk

335 40000 10000 Clerk

400 32000 7500 Salesman

451 28000 7500 Salesman

(i) To display W_ID Firstname, address andCity of all employees living in New York fromthe Table WORKERs

Ans: select W_ID ,firstname,address,city from workers where city=”New York”

(ii) To display the content of workers table in ascending order of LASTNAME.

Ans:Select * from Worker Order By lastname Asc

(iii) To display the FIRSTNAME, LASTNAME and Total Salary of all Clerks from the tables WORKERS And DESIG, where Total salary is calculated as Salary + benifts.

Ans: Select firstname, lastname, salary+benefits where worker.w_id=desg.w_id and Designation=”Clerk”

(iv) To display the minimum salary among managers and Clerks from the tables DESIG.

Ans: (Try This Answer)

(v) SELECT FIRSTNAME, SALARY FROM WORKERS, DESIG WHERE DESIGINATION = “MANAGER” AND WORKERS.W_ID = DESIGN.W_ID

Ans: FIRSTNAME SALARY

Sam 75000

Manila 70000

George 75000

(vi)SELECT COUNT(DISTINCT DESIGNATION) FROM DESIGN ;

Ans: 4

(vii) SELECT DESIGNATION, SUM(SALARY) FROM DESIG GROUP BY DESIGNATION HAVING COUNT (*) < 3;

Ans: Designation Sum(Salary)

Director 85000

Salesman 60000

(viii) SELECT SUM(BENIFTS) FROM DESIG WHERE DESIGINATION =”salesman”;

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