Select One Option Correct from the following A charge +q is fixed at each of the points
on the x-axis and a charge -q is fixed at each of the points
, Then, the potential at the origin due to the above system of charges is
(A) zero
(B) ![\frac{q}{8 \pi \epsilon_0 x_0 \ln 2} \frac{q}{8 \pi \epsilon_0 x_0 \ln 2}](https://tex.z-dn.net/?f=+%5Cfrac%7Bq%7D%7B8+%5Cpi+%5Cepsilon_0+x_0+%5Cln+2%7D)
(C) infinite
(D)
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(B)
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