Physics, asked by ISOLATEDREX6433, 11 months ago

Select One Option Correct from the following:Two identical metal plates are given positive charges q_1 and q_2 (\  \textless \ q_1) respectively. If they are now brought close together to form a parallel platecapacitor with capacitance C, the potential difference between them i
(A) \frac{q_1+q_2}{2C}
(B) \frac{q_1+q_2}{C}
(C) \frac{q_1-q_2}{C}
(D) \frac{q_1-q_2}{2C}

Answers

Answered by Anonymous
0

option C is the answer because it is matching with the formula.....

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