Select the correct answer from each drop-down menu. The molecule carbon disulfide (CS2) is nonpolar and has only London dispersion forces between the molecules. Carbon tetrachloride (CCl4) is also nonpolar but is made of larger molecules that are more strongly affected by London dispersion forces. Based on this information, CS2 likely has a melting point and a vapor pressure when compared with CCl4.
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The correct answer is that the melting point of CCl₄ is greater in comparison to CS₂, while the vapor pressure of CS₂ is greater than CCl₄.
As both the molecules are non-polar, the forces of attraction for CCl₄ are comparatively stronger as it is a bigger molecule. It is known that stronger the forces of attraction, higher is the melting point as more heat is needed to dissociate the bonds.
On the other hand, stronger the forces of attraction, lower is the vapor pressure as the molecules are more tightly bonded and less molecules attains the vapor phase. So, melting point of CCl₄ is higher, however, its vapor pressure is lesser in comparison to CS₂.
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