Question

Select the correct answer from each drop-down menu.
When p2 – 4p is subtracted from p2 + p – 6, the result is . To get p – 9, subtract from this result.

Answer 1

When $p^{2}$-4p is subtracted from $p^{2} +p-6$ we have:

$p^{2}+p-6-(p^{2}-4p)$=5p-6.

To get p – 9, subtract from this result x:

5p-6-x=p-9

5p-6-p+9=x.

x=4p+3.

When $p^{2}$-4p is subtracted from $p^{2} +p-6$  the result is 5p-6.

To get p – 9, subtract from this result 4p+3.

Answer 2

Answer:

$4p+3$

Step-by-step explanation:

First we are given that $p^{2} -4p$ is subtracted from

$p^{2}+p-6$:

⇒$p^{2}+p-6-(p^{2} -4p)$

⇒$p^{2}+p-6-p^{2} +4p$

⇒$5p-6$

The result is $5p-6$

Now we are given that to get p – 9, subtract from this result.

thus,  $5p-6-(p-9)$

⇒  $5p-6-p+9$

⇒  $4p+3$

Hence the resultant is  $4p+3$