Self a has 4/5th of the number of books that self b has.if 25% of the books in a are transfer to b and then 25% of the books from b transfered to a ,then the percentage of the total number of books a will have is
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Hello.
Let the number of books in shelf B be 100.
∴ Number of books in shelf A = {(100 x 4)/5} = 80
On transferring 25% i.e.,of books of shelf A to shelf B, the books on
shelf B = {100 + (80 x 25)/100}
B = 100 + 20 = 120
Books left in shelf A = 80-20 = 60
Again, on transferring 1/4th books of shelf B to shelf A, the books on
shelf A = {60 + (120/4)} = 90
Total no of books in A and B = 120 +60 = 180
Required percentage of books on shelf A = (90/180) x 100 = 50%.
Hope it helps
Let the number of books in shelf B be 100.
∴ Number of books in shelf A = {(100 x 4)/5} = 80
On transferring 25% i.e.,of books of shelf A to shelf B, the books on
shelf B = {100 + (80 x 25)/100}
B = 100 + 20 = 120
Books left in shelf A = 80-20 = 60
Again, on transferring 1/4th books of shelf B to shelf A, the books on
shelf A = {60 + (120/4)} = 90
Total no of books in A and B = 120 +60 = 180
Required percentage of books on shelf A = (90/180) x 100 = 50%.
Hope it helps
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