Math, asked by aashi06, 1 year ago

selling price of a toy car is rupees 540 if the profit made by shopkeeper is 20% what is the cost price of this toy

ayush9268: Find the two parallel sides of a trapezium whose area is 1.6 square metre, altitude is 10dm and one of the parallel sides is longer than the other by 8 metre.

Answers

Answered by harshitpanwar

SP=540
P%=20%
CP=100×SP/100+P%
=100×540/100+20
=100×540/120
=RS 450

abhishekagnihotri738: 100×540=100+20% =450

gauravkrknp: what?

abhishekagnihotri738: 100×540 = 100+20%
54000÷120
450 ans

gauravkrknp: answer is correct but I'm telling I solve this question only 2 lines..

princesssarkar: follow me

aryan1753: good

Answered by Anonymous

Solutions :-

We have,

Selling price (S.P.) = Rs 540

Profit % = 20%

Now,

Find the cost price (C.P.) :-

C.P. = (S.P× 100)/(100 + Profit)

= (540 × 100)/(100+20)

= 54000/120

= 450

Hence,

The cost price of toy is Rs 450

princesssarkar: follow me

Anonymous: stop :)

princesssarkar: follow me

princesssarkar: yes

princesssarkar: thank u

Previous Question

Next Question