Math, asked by aashi06, 1 year ago

selling price of a toy car is rupees 540 if the profit made by shopkeeper is 20% what is the cost price of this toy


ayush9268: Find the two parallel sides of a trapezium whose area is 1.6 square metre, altitude is 10dm and one of the parallel sides is longer than the other by 8 metre.

Answers

Answered by harshitpanwar
65
SP=540
P%=20%
CP=100×SP/100+P%
=100×540/100+20
=100×540/120
=RS 450

abhishekagnihotri738: 100×540=100+20% =450
gauravkrknp: what?
abhishekagnihotri738: 100×540 = 100+20%
54000÷120
450 ans
gauravkrknp: answer is correct but I'm telling I solve this question only 2 lines..
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aryan1753: good
Answered by Anonymous
58

Solutions :-





We have,




Selling price (S.P.) = Rs 540



Profit % = 20%




Now,



Find the cost price (C.P.) :-



C.P. = (S.P× 100)/(100 + Profit)


= (540 × 100)/(100+20)


= 54000/120


= 450





Hence,



The cost price of  toy is Rs 450




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