Question

Semi perimeter of a scalene triangle with side K, 2k, 3K is OR Calculate the area of an equilateral triangle whose perimeter is 60 cm ​

Answer 1

Q 1 : Semi perimeter of a scalene triangle with side K, 2k, 3K is ...

solution : scalene triangle : all three sides of triangle are different.

perimeter of triangle = sum of side lengths

here side lengths of triangle are k, 2k , 3k

so, perimeter = k + 2k + 3k = 6k

we know, semi perimeter = perimeter/2

= 6k/2 = 3k

Therefore the semi perimeter of given triangle is 3k.

Q 2 : Calculate the area of an equilateral triangle whose perimeter is 60 cm.

solution : perimeter of equilateral triangle = 3 × side length

⇒60 cm = 3 × side length

⇒side length = 60/3 = 20 cm

now area of equilateral triangle = √3/4 × (side length)²

= √3/4 × (20 cm)²

= √3/4 × 400 cm²

= 100√3 cm²

Therefore the area of triangle is 100√3 cm²

also read similar questions : Calculate the area and the height of an equilateral triangle whose perimeter is 60 cm.

https://brainly.in/question/28223110

Semi perimeter of equilateral triangle is 45 cm . Find the area of equilateral triangle

https://brainly.in/question/6108349

Answer 2

Question

Semi perimeter of a scalene triangle with side K, 2k, 3K is:

Answer

Semi Perimeter (s) = a+b+c         K+2K+3K            6K

                                ------------ = ------------------- = ------------- = 3K

                                      2                     2                   2

Question

Calculate the area of an equilateral triangle whose perimeter is 60 cm

Answer

x+x+x= 60

3x=60

x=60

   --- = 20

    3

∴ The three sides of equilateral triangle is 20 cm

area of an equilateral triangle = $\sqrt{3}$         $\sqrt{3}$  

                                                    ------ $a^{2}$ = ----- ×$20^{2}$

                                                      4             4

                                                               = 100$\sqrt{3\\}$

Hope it helps....

Please mark me as brainliest because I barely have any...