Question

send me answer this question ​

Answer 1

Step-by-step explanation:

y = 3x²+ x - 100

dy/dx = 6x + 1

[ derivative of constant 100 is zero]

Answer 2

QUESTION :–

• If y = 3x² + x - 100 , then dy/dx is :

(A) 6x

(B) 6x + 1

(C) 6x + 1 - 100

(D) x³ + x² - 100x

ANSWER :–

GIVEN :–

• A function y = 3x² + x - 100.

TO FIND :–

• dy/dx = ?

SOLUTION :–

$\\ \implies{ \bold{y = 3 {x}^{2} + x - 100 }}$

• Using identity –

$\\ \: \dashrightarrow \: { \bold{ \dfrac{d( {x}^{n} )}{dx} = n {x}^{n - 1} }}$

• Now Differentiate with respect to 'x' –

$\\ \implies{ \bold{ \dfrac{dy}{dx} = 3 \dfrac{d( {x}^{2}) }{dx} + \dfrac{d(x)}{dx} - \dfrac{d(100)}{dx} }}$

$\\ \implies{ \bold{ \dfrac{dy}{dx} = 3 (2x)+1 - 0 }}$

$\\ \implies \large { \boxed{ \bold{ \dfrac{dy}{dx} =6x + 1}}}$

▪︎ Hence , Option (B) is correct.