Question

Separate equations of lines for a pair of lines whose equation is r + - 12y2 = 0, are
x + 4y = 0 and x + 3y = 0
(b) 2x - 3y = 0 and r- 4v = 0
(c) X-6v = 0 and x-3y = 0
(d) 1 + 4y = 0 and r-3v = 0​

Answer 1

Answer:

Correct Answer: B) 

Step-by-step explanation:

Two pairs of straight lines have the equations y 2+xy−12x2=0 and ax2+2hxy+by2=0. One line will be common among them if : A ...

y^2 + xy - 12x^2 = 0 y^2 + 4xy - 3xy - 12y^2 = 0 y(y + 4x) - 3x(y + 4x) = 0 (y + 4x)(y - 3x) = 0 So, y = 3x or y = - 4x are the two straight lines represented