Physics, asked by sinhadamini551, 2 months ago

Separation between the coherent sources formed by a biprism is 1.75 mm. If the biprism is illuminated by a sodium lam which emits light of wavelength = 589 nm, calculate the fringe: width observed at a distance of 1 m from the light source.
a. 3.36 x 10^-4 m
b. 4.16 x 10^-5 m
c. 5.26 x 10^-7 m
d. 6.62 x 10^-6m​

Answers

Answered by shewtachoudhary981
0

Answer:

3.36*10=$°¶|{|hrjhekehdjk

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