Question

Set of four quantum numbers for the valence (outermost) electron of rubidium (z = 11) is

Answer 1

Answer:

So, the quantum numbers are n=5,l=0; (for s-orbital) m=0 $(\because m = + l\,to\, - l)$ , s=$ + \dfrac{1}{2}$ or $ - \dfrac{1}{2}$ . Rubidium is a chemical element with atomic number 37 which means there are 37 protons and 37 electrons in the atomic structure.

Explanation: