Math, asked by vk18022006, 7 hours ago

* Set up an equation for each of the following cases.
1. Tanay obtained 98 marks in a mathematics test. His score is the highest in the class and it is also 8 more than three times the lowest score. (Hint: Take the lowest score to be I.)

2. Sheila's father is three times as old as her. The sum of their ages is 56 years. (Hint: Take Sheila's age to be x years.)

3. Sum of two numbers is 39. The greater number is 7 more than the smaller number. (Hint: Take the smaller number to be n.)​

Answers

Answered by asga950652
1

tena obtained 98 marks in mathematics test

Answered by sujalshinde681
3

Step-by-step explanation:

1) Let, the highest score be x and the lowest score be y.

y = 8x

8x - y = 98

2) Let, the Shaila's age be x years and her father's age be y years .

x = 3y

x - 3y = 56

3) Let, the greater number be x and the smaller number be y.

x = y + 7

x - y = 7 + 39

x - y = 46

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