Math, asked by Madhushri, 1 year ago

Sets- 9,10,11,12. I can't understand the question. Please help me with the answer.

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Answers

Answered by NiranjanSasi
1
n(A∪B)=n(A)+n(B)-n(A∩B)
therefore, 30=15+n(B)-6
therefore, n(B)=21

Madhushri: Thanks!!
Answered by TheRuhanikaDhawan
1
n(P∪Q) = n(P) + n(Q) - n(P∩Q)
substituting the values

15 = 10 + n(Q) - 5
15 = 5 + n( Q)

n(Q) = 10
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n(T∪C) = n(T) + n(C) - n(T∩C)substituting the values
35 = 20 + 22 - n(T∩C)
35 = 44  - n(T∩C)

 n(T∩C) = 9
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n(P∪Q) = n(P) + n(Q) - n(P∩Q)
substituting the values

65 =  45 + 35 - n(P∩Q)
65 = 80 - n(P∩Q)

n(P∩Q) = 15
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n(A∪B)=n(A)+n(B)-n(A∩B)
substituting the values

30 = 15 + n(B) - 6
30 = 9 + n(B)

n(B) = 21
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TheRuhanikaDhawan: thanks
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