Math, asked by pspadmasahay, 7 months ago

Seven squares with side lengths 1, 2, 2, 2, 3,
4, and 5 units are fit together without any
gaps or overlaps, to form a rectangle. What
is the shorter side length of the rectangle?​

Answers

Answered by RvChaudharY50
19

Given :-

  • Seven squares with side lengths 1, 2, 2, 2, 3,
  • 4, and 5 units are fit together without any
  • gaps or overlaps, to form a rectangle.

To find :-

  • What is the shorter side length of the rectangle ?

Solution :-

it has been given that, their is no gap between the squares, ans they are not overlapping .

Suppose if we assume that , first we put square with smallest side that is 1 unit. Than on right or left we start putting rest squares in increasing order. (Lets assume on right side .)

→ 1 unit → 2 unit → 2 unit → 2 unit → 3 unit → 4 unit → 5 unit . { with no gap} .

Than,

on Bottom , Total side Length becomes = 1 + 2 + 2 + 2 + 3 + 4 + 5 = 19 units. = Larger side of the rectangle.

Now,

when we see on right most side , we have largest square with units is their.

Therefore,

if we want to make a boundry along the new figure so formed , (rectangle) , we must need our breadth to be 5 units, so the right most Square can fit exactly without any gap .

Hence,

we can conclude that, The shorter side length of the rectangle is 5 units.

Answered by MayankDixit27
0

Answer:

7 is the ans...

Step-by-step explanation:

(1×1)+(2×2)+(2×2)+(2×2)+(3×3)+(4×4)+(5×5)= 63

63= area of the rectangle

63 ÷ 9 (one of its factors)

=7

they both are sides 9×7= 63

7<9 hence, proven...

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