Question

seven times a positive two digit number is equal to for times the number obtained by reversing the digits of the difference between the digits is 3 find the number​

Answer 1

Answer:

Let the tens digit be y and ones digit be x

Explanation:

7 (10y + x) 4 (10x+ y)

70y + 7x = 40x + 4y

66y = 33x

x = 2y _1

x - y = 3 _2

substitute

2y - y = 3

y = 3

x = 2y

x = 3

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

2 b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.