Seven times a two digit number is equal to four time the number obtained by reversing te order of its digits. If the difference of digits is 3. Find the number
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Answered by
0
7(10x+y) = 4(10y+x)
66x= 33y
2x = y
2(y-3) = y
y= 6
no. = 36
66x= 33y
2x = y
2(y-3) = y
y= 6
no. = 36
Answered by
4
Answer:
36
Step-by-step explanation:
Let the unit digit be a and tenth unit be b .
So , number = 10 b + a
It's said number is seven times is equal to reversing the order of its digit.
= > 7 ( 10 b + a ) = 4 ( 10 a + b )
= > 70 b + 7 a = 40 a + 4 b
= > 66 b = 33 a
= > a = 2 b ... ( i )
Also given numbers' difference is 3 .
a - b = 3 ( ii )
From ( i ) and ( ii ) we get :
a b - b = 3
b = 3
= > a = 6
Hence number = > 30 + 6
= > 36.
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