Question

Seven times a two digit number is equal to four times the number obtained by reversing the order of digits. the sum of the digits of the number is 3.Find the number.

Answer 1

QUESTION:-

Seven times a two digit number is equal to four times the number obtained by reversing the order of digits. the sum of the digits of the number is 3.Find the number.

EXPLANATION:-

Let us assume that-:

Number at unit digit=x

number at ten's place=y

So the number so formed is-:

10x+y

One reversing-:

Number at unit digit-:y

Number at ten's place=y

So the number formed is -:

10x+y

ATQ

We can write-:

→7(10y+x)=4(10x+y)

→70y+7x=40x+4y

→70y=40x+4y-7x

→70y=33x+4y

→66y=33x

→66y/33=x

→x=2y             (i)

It is also given that-:

x-y=3                 (ii)

Substitute x=2y in (i)

→x-y=3

→2y-y=3

→y=3

Put y=3 in (ii)

→x-y=3

→x-3=3

→x=6

So the number is -:

⇒10y+x

⇒10×3+6

⇒30+6

⇒36

Answer 2

Step-by-step explanation:

Question :

Seven times a two digit number is equal to four times the number obtained by reversing the order of digits. the sum of the digits of the number is 3.Find the number.

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Answer :

Let,

Number at one's place = x

Number at ten's place = y

Therefore the number will be = (10x+y)

$\red{\boxed{According \: \: to \: the \: \: question}}$

7(10x+y) = 4 (10y+x)

$\implies$ 70x +7y = 40y+ 4x

$\implies$ 66x = 33y

$\implies$ 2x=y

$\implies$ x = y/2

It is given that the difference between them is 3. Since x is less then

y - x = 3

Putting the value of x

y - y/2 = 3

y/2 = 3

y = 6

$\blue{\boxed{Therefore \: x \:= 3}}$

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Final Result :

Hence the original number is 36 and the reversed number be 63.