Question

seven times a two digit number is equal to the four times the number obtained by reversing the order of the digits. if the difference of the digits is 3 determine the number

Answer 1

Answer:

Step-by-step explanation:

Let the number in tens place be x and ones place be y. So

X-Y =3.... (Given).....(1)

7(10x+y)= 4(10y+x)......... (2)

70x+ 7y= 40y + 4x

66x= 33y

Y = 2x..... (3)

Substituting 3 in 1,

X - 2x =3

X = -3

Y= -6

Hope u found it helpful

Answer 2

Answer:

36

Step-by-step explanation:

Let the unit digit be a and tenth unit be b .

So , number = 10 b + a

It's said number is seven times is equal to reversing the order of its digit.

= > 7 ( 10 b + a ) = 4 ( 10 a + b )

= > 70 b + 7 a = 40 a + 4 b

= > 66 b = 33 a

= > a = 2 b ... ( i )

Also given numbers' difference is 3 .

a - b = 3  ( ii )

From ( i ) and ( ii ) we get :

a b - b = 3

b = 3

= > a = 6

Hence number = > 30 + 6

= > 36.