Math, asked by mrlooseronline1221, 15 days ago

Seven years ago Ram's age was four times the square of Sita's age. Three years later Sita's age will be two fifth of Ram's age. then their present ages are​

Answers

Answered by gyaneshwarsingh882
0

Answer:

Step-by-step explanation:

Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x  

2

 years.

Swati's present age =(x+7) years, Varun's present age=(5x  

2

+7) years

Three years hence, we have

Swati's age (x+7+3) years =(x+10) years

Varun's age =(5x  

2

+7+3)=(5x  

2

+10)

It is given that three years hence Swati's age wil be  

5

2

 of Varun's age

∴x+10=  

5

2

(5x  

2

+10)

⇒x+10=2x  

2

+4

⇒2x  

2

−x−6=0

⇒2x  

2

−4x+3x−6=0

⇒(2x+3)(x−2)=0

⇒x−2=0⇒x=2

Hence Swati's present age =(2+7) years =9 years

Varun's present age =(5×x  

2

+7) years =27 years

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