Question

seven years ago varun's age was five times the square of swati age .three years hence swati age will be two fifth of varun age find their present age

Answer 1

Answer:

Varun's present age = x

swathi's present age = y

given ,

x-7 = 5(y-7) ------(1)

y+3 = 2/5 (x +3)

5y+ 15 = 2x +9

2x = 5y+9 ------- (2)

x = 5y +9/2

substitute x in eq (1)

we get , 2y^2-29y+99=0

solve by quadratic formula to get y=9

sustitute y in (2) to get X = 27 .

therefore varun's age is 27 years and swati's age is 9 years!

I hope it helps !!!

Answer 2

Answer:

Step-by-step explanation:

Let seven years, age of Swati was x years and age of Varun was 5x² years

Present age of Swati = ( x + 7 ) years

Present age of Varun = ( 5x² + 7 ) years

Given, after 3 years swati's age will be 2 / 5 of Varun's age.

Age of Swati after 3 years = ( x + 7 + 3 ) years = ( x + 10 ) years

Age of Varun after 3 years = ( 5x² + 7 + 3 ) years = ( 5x² + 10 ) years

Given, age of Swati after 3 years = age of varun after 3 years

( x + 10 ) = 2 / 5 × ( 5x² + 10 )

( x + 10 ) = 2( x² + 2 )

x + 10 = 2x² + 4

2x² - x + 4 - 10 = 0

2x² - x - 6 = 0

2x² - 4x + 3x - 6 = 0

2x( x - 2 ) + 3( x - 2 ) = 0

x = 2 [ Age can't be negative ]

Therefore,

present age of Swati = ( 2 + 7 ) = 9 years

present age of Varun = 5(2)²+7=27 years

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