Seventy tickets of a theater show were sold for Rs.8000. If the tickets were sold in denominations of Rs.125 and Rs.75, how many tickets of each denomination were sold?
Answers
Answered by
36
let the no. of 125-rupees ticket be X
So, no. of 75-rupees ticket be 70-X
ATQ,
125X+75(70-X)=8000
125X+5250-75X=8000
50X=2750
X=55
So, no. of ₹125 tickets =55 and No. of ₹75 tickets = 15
So, no. of 75-rupees ticket be 70-X
ATQ,
125X+75(70-X)=8000
125X+5250-75X=8000
50X=2750
X=55
So, no. of ₹125 tickets =55 and No. of ₹75 tickets = 15
Shaan12:
how are no. of 75 rupees notes 70- X ?????????
plz tell fast
the question says, total tickets :70
and there were denominations of Rs.125 and Rs.75 only
k...
so, if one is X other one is 70-X
thank you
Answered by
24
Total number of tickets = 70
Let N be the number of tickets sold in denominations of Rs 125.
So 70 - N will be the number of tickets sold in denominations of Rs 75.
Total proceedings from the tickets sale = Rs N * 125 + (70 - N) * 75
= Rs (50 * N + 5, 250)
= Rs 8, 000
50 N + 5, 250 = 8, 000
N = 2750/50 = 55
SO there were 55 tickets old in denominations of Rs 125 and 15 tickets of denominations of Rs 75.
Let N be the number of tickets sold in denominations of Rs 125.
So 70 - N will be the number of tickets sold in denominations of Rs 75.
Total proceedings from the tickets sale = Rs N * 125 + (70 - N) * 75
= Rs (50 * N + 5, 250)
= Rs 8, 000
50 N + 5, 250 = 8, 000
N = 2750/50 = 55
SO there were 55 tickets old in denominations of Rs 125 and 15 tickets of denominations of Rs 75.
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