Chemistry, asked by chandrabhankumar, 1 year ago

शुद्ध जल की मोलरता है(1) 100 (2)18 (3)55•6

Answers

Answered by kobenhavn
14

Answer: (3) 55•6

Explanation: As we know Density of pure water is = 1 g/ml

That means 1 gram of water is dissolved in 1 ml of solution.

Molarity : It is defined as the number of moles of solute present per Liter of solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{1g}{18g/mol}=0.056moles  

V_s = Volume of solution in ml

Molarity=\frac{0.0556\times 1000}{1ml}

Answered by RomeliaThurston
5

Answer: The correct answer is Option 3.

Explanation:

As we know,

Pure water has a density of 1g /mL

This means that 1 grams of water is dissolved in 1 mili liters of solution.

Molarity is a unit of concentration. It is defined as the number of moles of solute that are present in 1 Liter of solution.

The equation used to calculate the molarity of the solution is:

\text{Molarity}=\frac{m\times 1000}{M\times V_s\text{ (in mL)}}

where,

m = Given mass of solute = 1g

V_s = Volume of solution = 1mL

M = Molar mass of solute = 18 g/mol

Putting values in above equation, we get:

\text{Molarity}=\frac{1\times 1000}{18\times 1}

Molarity of water = 55.6 M

Hence, the correct answer is Option 3.

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