Math, asked by shanmukh3, 1 year ago

The least value of n that 1+3+5+7+........n terms ≥500 is

Answers

Answered by Rajivmohanty0
0
I think it is 485 it could we wrong
Answered by Anonymous
2
given,
a=1;d=3-1=2; also given that it should be be less than or equal to 500 so lets take an=500
         an=a+(n-1)d
          500=1+(n-1)2
         499/2=n-1
 
              since it is not exactly divisible it is not a term of this,
                so we will take one less than this that is 249
                   
  so,
an=249
   =a+(n-1)d
  249 =1+(n-1)2
 248=(n-1)2
124=n-1
n=125
               so there are 125 terms 
                   
                    HOPE IT HELPED U!!!


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