shanti is 3 years older than rani. ten years ago, shanti was twice as old as rani what is the present age of shanti? answer with solution
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Answered by
4
let age present of rani is x year
ATQ ,
age present of shanti is x+3 years
again ATQ ,
2 (x - 10 )= x +3 - 10
= > 2x - 20 = x - 7
=> x = 13 years
therefore present age shanti is 13 + 3 = 16 years
ATQ ,
age present of shanti is x+3 years
again ATQ ,
2 (x - 10 )= x +3 - 10
= > 2x - 20 = x - 7
=> x = 13 years
therefore present age shanti is 13 + 3 = 16 years
Answered by
2
Answer:
Shanti's age = 16 years
Rani's age = 13 years
Step-by-step explanation:
Given data
Shanti is 3 years older than Rani
and ten years ago shanti was twice as old as Rani
here we need to find Shanti and Rani's present ages
let x be the age of Rani's age years ago then shantis age is x+3 years
10 years ago shanti was twice as old as Rani
⇒ shanti's age (x+3) = 2x
x = 3
⇒ Rani's age x = 3
⇒ Shanti's age = x + 3 = 3 + 3 = 6 years
⇒ the present ages (ages after 10 years)
Shanti's age = 6 + 10 = 16 years
Rani's age = 3 +10 = 13 years
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