Question

Shanti Sweets stall was placing an order for making card for making cardboard box for packaging their sweets to size of boxer were required the bigger of the dimension 25 cm and 220 cm into 5 cm and the small of dimension 15 cm into 12 cm into 5 cm for all the overlap of 5% of the total surface area is required extra is the cost of the car bodies rupees 4000 CM square find the cost of a cardboard required for supplying 250 boxes of each kind

Answer 1

Answer:

Step-by-step explanation:

Class 9 Ncert question: 13.1, 7th one, right?

Pretty simple, if you understand the concept and formula!

Dimension of bigger box = 25 cm × 20 cm × 5 cm

Total surface area of bigger box = 2(lb + bh + lh)

  = 2(25×20 + 20×5 + 25×5)

 = 1450cm2

Dimension of smaller box = 15 cm × 12 cm × 5 cm

Total surface area of smaller box = 2(lb + bh + lh)

= 2(15×12 + 12×5 + 15×5)

= 630cm2

Total surface area of 250 boxes of each type = 250(1450 + 630)                                             =250×2080 cm2 = 520000 cm2

Extra area required = 5/100(1450 + 630) × 250 cm2 = 26000 cm2

Total Cardboard required = 520000 + 26000 cm2 = 546000 cm2

Total cost of cardboard sheet = ₹(546000 × 4)/1000 = ₹ 2184

Answer 2

Hi dear here is your answer.