Question

shaow that if x+y+z=0 then x cube +y cube+z cube =3xyz​

Answer 1

Answer:

X+y=-z

(x+y) ³=x³+y³+3xy(x+y)=-z³

x³+y³-3xyz=-z³. (since x+y = - z)

x³+y³+z³=3xyz

Answer 2

Answer:

Very easy as X+y+z=0X+y=-zX cube +y cube +z cube=3xyz(X+y)cube-3xy(x+y)+z cube = 3xyz(-z)cube -3xy(-z)+zcube =3xyz3xyz=3xyz  ...