sharmans age is four times his sons age.2 years ago his age was 1 more than 5 times his sons age find their ages
saqueebshaikh2641:
sorry my ans is wrong
Answers
Answered by
1
let sharmans age be x
his sons age be y
by first condition
x=4y
bye second condition
(x-1)=5(y-1)
4y-1=5y-5
4y-5y=-5+1
-1y=4
so...y=4
x=4y
so...
x=4×4
x=16
his sons age be y
by first condition
x=4y
bye second condition
(x-1)=5(y-1)
4y-1=5y-5
4y-5y=-5+1
-1y=4
so...y=4
x=4y
so...
x=4×4
x=16
Solved
Plug in and check with other options only this one will satisfy
If u want I ll do it in algebraic method
ok do it
X=4y, by 2 Nd condition, x-2 = 1+ 5(y-2)
now sub x in the 2nd equation,
4y -2 = 1+ 5y -10
y= 7 then x= 28
hope u understand
thank u
Answered by
2
Answer:
7 and 28
Step-by-step explanation:
By plugging in the answers method
Let x be the sharman age
Let y be the son age
1st condition, x= 4y
Put y= 7
X = 28
2years ago, 2 Nd condition,
28-2 = 1+ 5(7-2)
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