Question

Sharna is as twice as old as his son. After 4 years he is four times as old as his son was 9 years ago. what is their ages?

Answer 1

Let son's age be x years.
Therfore, Sharna's age = 2x
After 4 years,
Son's age = (x+4)
Sharna's age= 2x+4
ATQ,
2x+4=4(x+4)
Solve it and you get answer!

Answer 2

ANSWER FOR YOUR QUESTION IS AS FOLLOW'S:

STEP 1:

Consider Sharna's age as = 'x'
and  sharna's sons age as= ' y'


STEP 2:"
As per your question
"Sharna is as twice as old as his son"

so ,
x  = 2 y ------------(1) Equation 


STEP: 3:

Then it is given as "After 4 years he is four times as old as his son was 9 years ago" , we should find their respective ages now

using equation (1)

considering their age after 4 years ,( taking information from the question we get)

( x + 4 ) =  4  (  y  -  9  )  ( as it is said that 9 years ago substract nine from the equation and add 4 to the fathers age) 

then is we multiply terms on left we get,


(  x  +   4 ) = 4  y -   36 


2 y  +  4 =  4   y   -  36 ------( from equation 1)

now bring the numerical to one side and all the variables to other side



36   +   4 =    4   y -  2  y

40    =    2  y  ( bring 2 to the denominator now)

we get,

y  = 20 -------------so a we assumed before that 'y ' as son's age 



hence son's age = 20 years 
now fathers age  = from equation 1--- x= 2y  substitute the values , we get
                                x= 40 years 


hence , x ( sahrna ) = 40 
           y ( son )       = 20 


HOPE IT HELPS!!
SORRY FOR DELAY IN ANSWERING!
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COURTESY : FIRE FURRY:)