Sharukh starts from barabanki to fatehpur,1hour after ajay starts. Sharukh meets kajol 1.5 hours after sharukh starts. If the speed of the sharukh is at least 20km/h faster than the speed of the kajol what is the minimum speed of sharukh to overtake ajay before he meets kajol
Answers
Answer:
87.5 km
Explanation:
Complete Question :
Ajay and Kajol start towards each other at the same time from Barabanki and Fatehpur for their destinations Fatehpur and Barabanki respectively which are 300 km apart. They meet each other 120 km away from Barabanki. Shahrukh starts from Barabanki to Fatehpur, 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20 km/h faster than the speed of Kajol.
what is the minimum speed of sharukh to overtake ajay before he meets kajol
Ajay Covers 120 km
Kajol covers = 180 km
Let say speed of Kajol = 3K km/hr
Then Speed of Ajay = 2K km/hr (3K* 120/180)
Speed of Shahrukh ≥ 3K + 20 + c km/hr
1.5(3K + 20 + c) + 2.5*3K = 300
=> 12K + 1.5c = 270
=> K + 1.5c/12 = 22.5
=> K = 22.5 - 1.5c/12
1.5(3K + 20 + c ) > 2.5*2K
=> 4.5k + 30 + 1.5c > 5k
=> 0.5k < 30 + 1.5c
=> K < 60 + 3c
22.5 - 1.5c/12 < 60 + 3c
=> c < 0
Which can not be
So to find minimum speed of Shahrukh we need to find minimum speed of kajal
Kajol Speed = 3K = 3*22.5 = 67.5 km
Shahrukh speed = 67.5 + 20 = 87.5 km
Shahrukh will cover = 87.5 * 1.5 = 131.25 km
while Ajay will cover = 45 * 2.5 = 112.5 km
Answer:
Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than the speed of Kajol. What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol? This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.