Sharwend, Barney, and Ronnie share sweets according to the ratio 5:3:7. Ronnie gets 20 more sweets than Barney. Work out how many sweets Barney received.
Answers
Answer:15 sweets
sharwand:barney:ronnie=5:3:7
ronnei gets 20 +barney
I.e.if we take common multiple be x
5X,3x,7x.
ronnie =7X,barney=3x
7x=20+3x
7x-3x=20
4x=20
4x=20x=5
I.e.baeney received 3x=3×5 =15
Answer :
- Number of sweets with Barney = 15sweets
Explanation :
Given ,
Ratio of sweets with Sharwend, Barney, and Ronnie is 5:3:7.
According to the question :
Ronnie gets 20 more sweets than Barney.
Let , number of sweets with Sharwend, Barney, and Ronnie be 5x , 3x , 7x respectively.
=> Now, according to the question , we get
7x = 3x + 20.
As Ronnie have 20 more sweets than Barney.
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=> By solving ,
7x - 3x = 20
4x = 20
x = 20/4
x = 5 sweets.
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Now, by keeping the value of x we get,
Number of sweets with Sharwend = 5x = 5(5) = 25sweets.
Number of sweets with Barney = 3x = 3(5) = 15sweets.
Number of sweets with Ronnie = 7x = 7(5) = 35sweets.
Now, according to the question, we get