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Let the same common difference of two AP’s isd, Given that, the first term of first AP and second AP are 2 and 7 respectively, then the AP’s are
2,2 + d,2 + 2d,2 + 3d,.,.
and 7,7+ d, 7 +2d, 7+3d,…
Now, 10th terms of first and second AP’s are 2 + 9d and 7 + 9 d, respectively.
So, their difference is 7 + 9d – (2 + 9d) = 5
Also, 21st terms of first and second AP’s are 2 + 20d and 7 + 20d, respectively.
So, their difference is 7 + 20d – (2 + 9d) = 5
Also, if the a„ and bn are the nth terms of first and second AP.
Then, bn -an = [7 + (n-1)d)] – [2 + (n-1)d] = 5
Hence, the difference between any two corresponding terms of such AP’s is the same as the difference between their first terms.
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