Question

Shatabdi Express takes 6 hours to travel from New Delhi to Lucknow at the speed of 80 km per hour find the distance between the two cities.​

Answer 1

${\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}$

$\mathfrak{\underline{AnswEr:-}}$

• The distance from New Delhi to Lucknow = 480 km

$\mathfrak{\underline{Given:-}}$

• The Shatabdi Express takes 6 hours to travel from New Delhi to Lucknow at the speed of 80 km/hour.

$\mathfrak{\underline{Need\:To\: Find:-}}$

• The distance from New Delhi to Lucknow = ?

${\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}$

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\star\large{\boxed{\sf\red{Distance = Speed \times Time }}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {Distance = 80\:km \times 6\:hours}$

$\longrightarrow \sf {Distance = 480\:km}$

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

• The distance from New Delhi to Lucknow is 480 km.

$\rule{200}{2}$

Answer 2

Question:

Shatabdi Express takes 6 hours to travel from New Delhi to Lucknow at the speed of 80 km per hour find the distance between the two cities.

Solution:

${\underline {\underline {\boxed {\bf {\red { Given: }}}}}}$

• $\sf { Time \: taken = 6 \: hours }$

• $\sf { Speed = 80 \: km/h }$

${\underline {\underline {\boxed {\bf {\red { To \: find: }}}}}}$

• $\sf { Total \: distance \: between \: two \: cities }$

${\underline {\underline {\boxed {\bf {\red { Calculation: }}}}}}$

We know that,

• ${\underline {\underline {\boxed {\bf {\green { Distance = Speed \times time }}}}}}$

According to formula substituting values-

$\sf { \longrightarrow Distance = {80 km}^{-h} \times 6 hours }$

$\sf\green { \longrightarrow Distance = 480 km}$

$\therefore$ The distance between the two cities is 480km.

______________________

Some important formulae:

• ${\underline {\underline {\boxed {\rm {\orange { Distance= Speed \times Time }}}}}}$

• ${\underline {\underline {\boxed {\rm {\orange { Speed = \frac{Distance}{Time} }}}}}}$

• ${\underline {\underline {\boxed {\rm {\orange { Speed_{avg} = \frac{Distance_{avg}}{Time_{avg}} }}}}}}$

• ${\underline {\underline {\boxed {\rm {\orange { s = v - u }}}}}}$

• s is displacement
• v is final velocity
• u is initial velcity

• ${\underline {\underline {\boxed {\rm {\orange { v = \frac{s}{t} }}}}}}$

• v is velocity
• s is displacement
• t is time

• ${\underline {\underline {\boxed {\rm {\orange { a = \frac{v-u}{t} }}}}}}$

• a is acceleration
• v is final velocity
• u is initial velocity

Three equations of motion

• ${\underline {\underline {\boxed {\rm {\orange { v = u + at }}}}}}$

• ${\underline {\underline {\boxed {\rm {\orange {2as = {v}^{2}- {u}^{2} }}}}}}$

• ${\underline {\underline {\boxed {\rm {\orange {s = ut + \frac{1}{2}a{t}^{2} }}}}}}$.

Here,

• v is final velocity
• u is initial velocity
• a is acceleration
• s is displacement
• t is time

____________________