Question

Shaw that energy in conserve I. case of a free falling in body​

Answer 1

Answer:

In the case of a freely falling body, it is the mechanical energy of the system that is conserved. Mechanical energy (E) is the sum of the potential energy (U) and the kinetic energy (K) of the freely falling body. Therefore, E=K+U=constant.

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Answer 2

Answer:

Law of conservation of energy states that:−

Energy can neither be created nor be destroyed.

Energy transforms from one form to another form and, potential energy+ kinetic energy= constant

Proof:−

At point A

K.E=0m/s

P.E=mgh

P.E=mgh

At point B,

K.E.,

2gh=V

2

−O

2

V

2

=2gx

K.E=

2

1

mV

2

K.E=

2

1

m.2gx

K.E=mgx-----------------------------(1)

P.E=mgh

P.E=m.g.(h−x)

P.E=mgh−mgx---------------------(2)

from(1) and (2)

K.E+P.E constant

mgx+mgh−mgx=mgh

mgh=mgh

At point C,

P.E=0

2gh=v

2

−u

2

( initial velocity =0 m/s)

2gh=v

2

K.E=

2

1

.m.v

K.E=

2

1

.m.2gh

K.E=mgh

Thus, in all the points the energy is same.