Math, asked by aadithyaram2007, 10 months ago

sheena is 15 years younger than her brother shyam. Ten years from now shyam will be twice as old as sheena. find the present ages

Answers

Answered by BrainlyRaaz
151

Given :

  • Sheena is 15 years younger than her brother shyam.
  • Ten years from now shyam will be twice as old as sheena.

To find :

  • Their present ages =?

Step-by-step explanation :

Let, the present age of Shyam's be, x

Then, the present age of Sheena's be, x + 15

After 10 years Sheen's age =  x + 15 + 10

                         = x + 25

After 10 years Shyam's age = x + 10

According to question ,

➮ x+25 = 2(x+10)

              

➮ x+25 = 2x + 20

            

➮ 25 = 2x + 20 - x

            

➮ 25 = x+20

            

➮ 25 - 20 =x

            

➮ 5 = x

or x = 5

Therefore, We got the value of, x = 5 year's.

Hence,

Present age of Shyam's = 5 years

And, Present age of Sheena's = x + 15

                                      = 5 + 15

                                      = 20 years

Answered by TheSentinel
78

Answer :

Present ages of Sheena and Shyam are 20 years and 5 years respectively.

Given:

Sheena is 15 years younger than her brother shyam.

➛Ten years from now shyam will be twice as old as sheena.

To Find:

Present ages of Sheena and Shyam.

Solution:

     Let, The Present age of Shyam ( in Years ) = m

    

According to first condition,

Present age of Sheena = m + 15

  

  Now , According to second condition,

After 10 years ,

      

Sheena's age =  m + 15 + 10

Sheena's age = m + 25

                        

     Shyam's age = m + 10

             ➞m + 25 = 2( m + 10 )

              ➞m + 25 = 2m + 20

             ➞25 = 2m + 20 - m

             ➞ 25 = m + 20

             ➞ 25 - 20 = m

             ➞ 5 = m

i.e m = 5

Therefore,

Present age of Shyam = 5 years

and Present age of Sheena =

➞ m + 15

             ➞  5+15

             ➞ 20 years

Present age of Sheena =20 years.

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