Math, asked by ammananna807, 11 months ago

Sheena read 1/5 of a novel on the Frist day she read 2/3 of the remaining pages on the second day she finished reading the novel on the third day how many pages did she read on the third day if the novel had 750 pages​

Answers

Answered by dhruvkoul
4

Answer:

Step-by-step explanation:

no. of pages read on 1st day=1/5*750

                                               =150

no. of pages read on 2nd day=2/3*750

                                                 =500

therfore no. of pages read on 3rd day=750-(500+150)

                                                              =100 pages

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