Question

sheila is now 15 years older than her younger brother sanjay.ten years from now,sheila will be twice as old as sanjay.find the present age of each of them 

Answer 1

Answer :
     Let the Present age of Sanjay (in Years ) = x
     Therefore , Present age of Sheila = x+15
     After 10 years ,
       Shielas age =  x+15+10
                         = x+25
       sanjay's age = x+10

According to question ,
               x+25 = 2(x+10)
               x+25 = 2x + 20
             25 = 2x + 20 - x
             25 = x+20
             25 - 20 =x
             5 =x
or x=5
Hence Present age of Sanjay = 5 years
and Present age of Shiela = x+15
                                      = 5+15
                                       = 20 years

Hope this helps you!!

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Answer 2

Answer:

sheila's age = 20yrs  sanjay's age = 5yrs

Step-by-step explanation:

let the present age of sanjay = x yrs

and present age of sheila = x+5yrs

after 10 yrs

sheila's age = x + 15 + 10 = x + 25

sanjay's age = x + 10

according to the question

x+25 = 2 ( x + 10 )

x + 25 = 2x + 20

transpose x to RHS and +20 to LHS

25 - 20 = 2x - x

5 = x

hence present age of sanjay = x = 5 yrs

present age of sheila = x + 15 = 5 + 15 = 20 yrs

hope it helps you