Shekhar speaks truth in 1/2 of the cases and mohit in 4/5. Contradict each other?
Answers
Answer: ½ or 50%
Step-by-step explanation:
Assuming theta the question is related to probability. Hence the approach to solve the problem will be as follows:
Let “A-true” be the event of Shekhar speaking truth and “A-lie” be the event of Shekhar speaking lie. Also, let “B-true” be the event of Mohit speaking truth and “B-lie” be the event of Mohit speaking lie.
Shekhar speaks the truth in ½ of the cases
∴ P(A-true) = 1/2
Mohit speaks truth in 4/5 of the cases
∴ P(B-true) = 4/5
Shekhar speaks lie in, P(A-lie) = 1 - 1/2 = ½ cases
Mohit speaks lie in, P(B-lie) = 1 – 4/5 = 1/5 cases
Hence, the probability of Shekhar and Mohit will contradict each other
= [P(A-true)*P(B-lie)] + [P(A-lie) + P(B-lie)]
= [1/2 * 1/5] + [1/2 * 4/5]
= 1/10 + 2/5
= ½ or 50%