Math, asked by kellywakker52, 3 months ago

Shikha deposited 2000 in a bank which pays 6% simple interest. She withdrew
700 at the end of the first year. What will be her balance after 3 years ?





please give the right process and answer ​

Answers

Answered by samruddhiDeshmukh
1

Answer:

Principal = Rs.2000

Rate of interest = 6 % per annum

Time period = 1 year

S.I = \( \frac{P\times\;R\times\;T}{100}\)

= \( \frac{2000\times\;6\times\;1}{100}\)

S.I = Rs.120

Total amount after one year = Principal + Interest

= Rs.2000 + Rs.120

= Rs.2120

Principal amount left = Rs.2120-Rs.700

= Rs.1420

Rate of interest = 6% per annum

Time period = 2 years

S.I = \( \frac{P\times\;R\times\;T}{100}\)

= \( \frac{1420\times\;6\times\;2}{100}\)

S.I = Rs.170.40

Total amount after 3 years = Principal + Interest

= Rs.1420 + Rs.170.40

= Rs.1590.40

Answered by chpavithra
1

Answer:

Shikha deposited 2000 in a bank which pays 6% simple interest. She withdrew

700 at the end of the first year. What will be her balance after 3 years ?

Rate of interest is given as 6% and Principle amount as Rs2000

Interest after 1 year= P*R*T/100 = 2000*6*1/100 = Rs 120

Net amount at the end of first year= Principle+ interest-Amount withdrawn=2000+120-700= Rs 1420

For the next 2 years, simple interest will be paid at the rate of 6% on the amount of Rs 1420 which is = 1420*6*2/100 =Rs 170.40

Balance after 3 years= 1420+170.40=Rs 1590.40

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