Question

shilpa walks 6 km towards south.from there towards east .then she walks 2km towards south.agaib she walks 3km towarda west howfar is she from the original position
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Answer 1

Answer:

As the distance covered by her in the east direction is not given, let me take it to be 3km as east and west get nullify or you can take it to be a

Initial distance is 6 km towards south

let the initial coordinates be( x,y)

Final coordinate x= distance covered in east - distance covered in west

                              = a-3 or 3-3 =0

Final y coordinates y = -(6+2)=-8

The distance of her from original position = √x²+y²= √a²+64 or√0²+64 =8

Answer 2

Let me correct your Question:

Shilpa walk 6 km two words South from there she walks 9 km two words East then she walks 2 km towards South and again she walks 3 km towards West how far is she from her original position?

Answer:10km

Step-by-step explanation:

1) The total distance travelled by Shilpa towards South is 6+2=8.

2)The total distance travelled by Shilpa towards East is 9-3=6.

3) Please refer attached image for better understanding.

4) Now, we need to find distance from her original position, so we need to use diagonal of rectangle formula i.e.

d = √( l^2 + w^2)[underroot of L square+W square that are both sides of rectangle]

5) By solving,

d = √( 8^2+ 6^2)

We get,

√100

So, 100 is underroot of 10.

The diagonal would be 10, means Shilpa is 10km far from her original position.